Maniaplanet Forum

Posted: **04 Mar 2013, 02:43**

I have several Lists. I want to keep PlayerLogins in one list at a time only. So when I add a PlayerLogin to one list(array) I want to remove it from all others.
just using List.remove gives "this value will be discarded" while compiling. Still seems to work but it interupts the compiling and I figure it might make the script really slow if it discards after several attempts to get and remove value.

So what I need some help with is to move a login from a list to a different while making sure that list is the only list that contain the login.

Example:
List A Superman,Hulk,Finn,Gir
List B Flash,Spiderman,Bender
List C Dr_Doom,Alex

Now I want to move Finn from list A to list B
So I add Finn to list B
Remove Finn from list A and C since I don't check if the list contains Finn and just want to make sure not to get duplicate.

Which is the best way to solve it?

Posted: **04 Mar 2013, 02:56**

if you are using php try:
array_pop
array_shift

Posted: **04 Mar 2013, 09:07**

MuNgLo wrote:just using List.remove gives "this value will be discarded" while compiling. Still seems to work but it interupts the compiling and I figure it might make the script really slow if it discards after several attempts to get and remove value.

try

Code: Select all

declare Temp = Array.remove(Login);

the message only shows that a value is thrown into the matrix without doing something with it

(.remove() returns the removed value)

MuNgLo wrote:So what I need some help with is to move a login from a list to a different while making sure that list is the only list that contain the login.

Example:
List A Superman,Hulk,Finn,Gir
List B Flash,Spiderman,Bender
List C Dr_Doom,Alex

Now I want to move Finn from list A to list B
So I add Finn to list B
Remove Finn from list A and C since I don't check if the list contains Finn and just want to make sure not to get duplicate.

Which is the best way to solve it?

i would suggest a method like this

Code: Select all

Void AddToArray(Text _Login, Text[] _Array) {
	declare Temp = Array1.remove(_Login);
	Temp = Array2.remove(_Login);
	Temp = Array3.remove(_Login);
	_Array.add(_Login);
}

so you only need one line to make sure that the value is only in the intended array and in none other

i'm not sure if there will be an error if you try to remove a value which isn't in an array! so you might want to test the existence of the value (i think there won't be an error, instead there will be Null returned, but you better try it yourself ^^)

Code: Select all

if (Array.exists(Login)) {
	declare Temp = Array.remove(Login);
}

//Edit: 200th post!

Posted: **04 Mar 2013, 10:47**

Removing a non-existing value shouldn't cause an error.

Posted: **04 Mar 2013, 17:57**

Thx guys.

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